Definitions
from Wiktionary, Creative Commons Attribution/Share-Alike License.
- adjective Lacking
divergence
Etymologies
from Wiktionary, Creative Commons Attribution/Share-Alike License
divergence + -less
Support
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Examples
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But there's no reason to require that the gravitational "field" be divergenceless.
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First, you are absolutely right that the divergence theorem establishes an exponent of exactly 2 for divergenceless vector fields in flat Euclidean space.
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But there's no reason to require that the gravitational "field" be divergenceless.
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But there's no reason to require that the gravitational "field" be divergenceless.
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First, you are absolutely right that the divergence theorem establishes an exponent of exactly 2 for divergenceless vector fields in flat Euclidean space.
Comments
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