sPtr

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* Purpose: to get * sPtr and return it to main so that I can print statements

DaniWeb IT Discussion Community myluvstefan 2010
The first destructor to execute would then delete * the dynamically allocated memory, and the other object's sPtr would * be undefined (meaning sPtr would be a DANGLING POINTER).

DaniWeb IT Discussion Community myluvstefan 2010
* Purpose: to get * sPtr and return it to main so that I can print statements

DaniWeb IT Discussion Community myluvstefan 2010
* Copy right. sPtr after the tmpStr. sPtr + the length that's already there ... so

DaniWeb IT Discussion Community myluvstefan 2010
* Copy sPtr into tmpStr.sPtr. strcpy (tmpStr. sPtr, sPtr); cout

DaniWeb IT Discussion Community myluvstefan 2010
* into sPtr. else if string2 is a null pointer, then I make sPtr an empty

DaniWeb IT Discussion Community myluvstefan 2010
* be undefined (meaning sPtr would be a DANGLING POINTER).

DaniWeb IT Discussion Community myluvstefan 2010
* the dynamically allocated memory, and the other object's sPtr would

DaniWeb IT Discussion Community myluvstefan 2010
* that I don't overwrite what I just put in tmpPtr.sPtr. strcpy (tmpStr. sPtr + length, right. sPtr); cout

DaniWeb IT Discussion Community myluvstefan 2010
* points to dynamically allocated memory char * sPtr;

DaniWeb IT Discussion Community myluvstefan 2010