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How do you show that for an nxn matrix A the eigenvalue being x, has an inverse and its eigenvalue is 1 / x?— Yahoo! Answers: Latest Questions
One eigenvector is a uniform superposition of all | S > | k >, k s S, with eigenvalue 1.— Recently Uploaded Slideshows
Generalized matrix inversion is not harder than matrix multiplication ai amg bc bi compiler datastructures decidability discretization eigenvalue fem functional green haskell irregular java krylov math neural-networks numerical optimization parallel photography physic poisson precond profiling simulation verification vm wake CiteULike organises scholarly (or academic) papers or literature and provides bibliographic (which means it makes bibliographies) for universities and higher education establishments.— CiteULike: Everyone's library
Apparently, the single-photon state is an eigenstate of the momentum operator, and is the eigenvalue (the momentum of a single photon).— Citizendium, the Citizens' Compendium - Recent changes [en]

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